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6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2
7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2
cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2
cos150
Video solution 1: 6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2
7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2
cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2
cos150
Video solution 2: 6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2
7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2
cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2
cos150
Find the value of : (i) sin 30^(@)+cos 60^(@) (ii) sin 0^(@)-cos 0^(
The_trigonometry_functions
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Bengali] Prove that: t a n 720^0-cos 270^0-sin 150^0cos 120^0=1/4
6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2 7cos120∘cos(90..
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Unit 1: Work with compound angles – National Curriculum (Vocational) Mathematics Level 4
The_trigonometry_functions
Unit 2: Use reduction formulae to simplify trig ratios – National Curriculum (Vocational) Mathematics Level 3
Find the values of : (i) tan (-30^(@)) (ii) sin 120^(@) (iii)
2. sin 60∘ cos 30∘ + cos 60∘ sin 30∘ - Noon Academy